10c^3-22c^2+4c=

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Solution for 10c^3-22c^2+4c= equation:


Simplifying
10c3 + -22c2 + 4c = 0

Reorder the terms:
4c + -22c2 + 10c3 = 0

Solving
4c + -22c2 + 10c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2c'.
2c(2 + -11c + 5c2) = 0

Factor a trinomial.
2c((1 + -5c)(2 + -1c)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(1 + -5c)' equal to zero and attempt to solve: Simplifying 1 + -5c = 0 Solving 1 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5c = 0 + -1 -5c = 0 + -1 Combine like terms: 0 + -1 = -1 -5c = -1 Divide each side by '-5'. c = 0.2 Simplifying c = 0.2

Subproblem 3

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {0, 0.2, 2}

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